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$10.00 Use calculus to find the points along th

  • From Mathematics: Calculus
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  • Due on Jul. 21, 2009
  • Asked on Jul 18, 2009 at 3:58:43PM
Asked by :
Losec20
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Q:
Use calculus to find the points along the path that are the shortest distance to each of the exhibits, using a slope of 2/3 for the path.
Exhibits are located at the points (3,1) and (6,6)
 

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calculus solution
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  • Posted on Jul 19, 2009 at 5:07:39PM
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GroundZero
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A:
Preview: ... point where the two lines intersect. We know that at that point, the two lines intersect, so we shall set them equal to each other and solve for x. Then we will take that x-value and plug it into the first line, thereby solving for y. That will give us the point (x0, y0). Sett ...
The full tutorial is about 297 words long plus attachments.

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Attachments:
RR_01.JPG (5K) (Preview)
Distance.JPG (48K) (Preview)
X0.JPG (5K) (Preview)
Y0.JPG (10K) (Preview)
 
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Solution with insight
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  • Posted on Jul 19, 2009 at 6:30:19PM
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PhDforU
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Preview: ... s point D.<br>6. The point D is located at:<br>( (x1+x2)/2, (y1+y2)/2 ),<br>where the two extreme points of B are:<br>(x1, y1) and (x2, y2). We know x1=3, y1=1, x2=6, y2=6.<br>7. Therefore D is at (9/2,7/2).<br>8. The line A must pass through D. Thus ...
The full tutorial is about 223 words long .