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# \$25.00Heat and Thermodynamics 2

• From Physics: General-Physics
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• Due on Mar. 03, 2012
• Asked on Feb. 29, 2012 at 09:24:21AM

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For this SLP, you will perform a simulation investigating three special processes - isobaric (constant pressure), isochoric (constant volume), and isothermal (constant temperature). - that can be derived from the ideal gas law.  The simulation is found at Background Info 1.  The simulation allows you to vary the pressure for an isobaric process, the volume for an isochoric process, and the temperature for an isothermal process.  The simulation shows how the system goes from one equilibrium state to another and the work that is done on or by the system, and how heat flows into or out of the system.

The variables are:

V1 = initial volume, dm3 (dm = decimeter = 10 cm)

V2 = final volume, dm3

P1 = initial pressure, kPa (absolute; that is, measured against vacuum)

P2 = final pressure, kPa

T1 = initial temperature, K

T2 = final temperature, K

Heat flow:     into system (red arrow points right)

out of system (red arrow points left)

Work done:    on system (blue arrow points up)

by system (blue arrow points down)

Experiment 1:

Isobaric (constant pressure) Process

P1 = P2 = 100 kPa

Fill in the blanks in the following table.

 V1 T1 V2 T2 Heat Work 1.00 300 0.5 150 out on 1.00 300 1.25 1.00 300 2.00 1.00 300 200 1.00 300 350 1.00 300 400

Show how these results illustrate the Ideal Gas Law for the special case of constant pressure.  (Hint:  Show that V1/T1 = V2/T2 for all the test conditions.)

__________

Experiment 2:

Isochoric (constant volume) process

V1 = V2 = 1.00 dm3

Fill in the blanks in the following table.

 P1 T1 P2 T2 Heat Work 100 300 66.7 200 100 300 400 100 300 500 100 300 75 100 300 150 100 300 200

Following a procedure similar to the one in Experiment 1, show how these results illustrate the Ideal Gas Law for the special case of constant volume.

__________

Experiment 3:

Isothermal (constant temperature) process

T1 = T2 = 300 K

Fill in the blanks in the following table:

 P1 V1 P2 V2 Heat Work 100 1.00 75 100 1.00 150 100 1.00 200 100 1.00 0.75 100 1.00 1.25 100 1.00 2.00

Following a procedure similar to the one in Experiment 1, show how these results illustrate the Ideal Gas Law for the special case of constant temperature.

The isothermal case deserves a special mention, because at first glance it seems to be just plain wrong.  Everybody knows that when you squeeze a quantity of gas, the volume goes down and the pressure goes up;  but the temperature ALSO goes up.  Ask any diesel mechanic!  So what's going on here?

Answer:  Either the volume is decreased (pressure increased) so slowly that the heat can escape, and the temperature remains a constant, OR the system is compressed to its new, smaller volume, and allowed to cool to its original temperature, before the new pressure is measured.  Which is definitely a lab experiment, and not an industrial process.

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• Posted on Feb. 29, 2012 at 09:27:59AM
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A:
Preview: ... g a procedure similar to the one in Experiment 1, show how these results illustrate the Ideal Gas Law for the special case of constant volume. Sample calculation We have at constant volume. P1 = 100, T1=300, P2=?, T2=400 Putting in the above equation, we get Here, volume is not changing; hence, no work will be done either on the system or by the system. Temperature is increasing; hence, heat flows towards the system. Similarly, other entries in the table are filled. In general, when temperature increases, heat flow is towards the system and vice-versa. Experiment 3: Isothermal (constant temperature) process T1 = T2 = 300 K Fill in the blanks in the following table: P1 V1 P2 V2 Heat Work P1V1 P2V2 Is P1V1=P2V2? 100 1.00 75 1.333 zero by 100 100 Yes 100 1.00 150 0.667 zero on 100 100 Yes 100 1.00 200 0.5 zero on 100 100 Yes 100 1.00 133.33 0.75 zero on 100 100 Yes 100 1.00 80 1.25 zero by 100 10 ...

The full tutorial is about 818 words long plus attachments.

Attachments:
Experiment.docx (32K) (Preview)

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Preview: ... swer ...

The full tutorial is about 3 words long plus attachments.

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Heat and Thermodynamics 2.doc (64K) (Preview)

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• Posted on Feb. 29, 2012 at 09:36:22AM
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Preview: ... the att ...

The full tutorial is about 4 words long plus attachments.

Attachments:
thermo.doc (64K) (Preview)

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100 % correct answer. My favourite topic in Engineering..Solved Earlier
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• Posted on Feb. 29, 2012 at 09:45:29AM
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