This question's due date has already passed. You may post a tutorial, but there's no guarantee that the original asker will purchase the tutorial. But other people might!

Question

$5.00 Help please

  • From Mathematics: Algebra
  • Closed, but you can still post tutorials
  • Due on Jun. 22, 2012
  • Asked on Jun. 19, 2012 at 06:43:36AM
Asked by :
choppas82
choppas82
Rating :No Rating
Questions Asked: 37
Tutorials Posted: 1,
Earned: $4.10
 
 
Q:

see attached


 
attachement
Attachments:
quizz6.doc (54K)
 

Available Tutorials to this Question
 
$5.00
A+ step-by-step solution for you(Quiz 6)
  • This tutorial was purchased 1 time and rated No Rating by students like you.
  • Posted on Jun. 19, 2012 at 07:21:05AM
Posted by :
arenasshuai
 
A:
Preview: ... ase chec ...
The full tutorial is about 6 words long plus attachments.

attachmentlogo

Attachments:
Solution_quiz_6_choppas82.doc (61K) (Preview)
Solution_quiz_6_choppas82.docx (39K) (Preview)
 
$2.80
complete solution to quiz 6 except no. 11 which is unclear
  • This tutorial hasn't been purchased yet.
  • Posted on Jun 21, 2012 at 12:19:19PM
Posted by :
wizmaster
wizmaster
Rating (12):A+
Questions Asked: 0
Tutorials Posted: 16,
Earned: $286.10
 
A:
Preview: ... t = (log25000 – log10000)/ (12log( 1 7.2/1200) ) t = 12.7532   9. a.  the continuous interest equation             A = p(e rt )           4000 = 2500 (e 5k )           e 5k = 1.6            lne 5k =ln1.6            5k = lnl.6             K = 0.0940 0r 9.4%, interest r      b.   A = p(e rt ) , exponential growth function      c.  A = p(e rt )           A = 2500(e 0.094*10 )           A = 6,400     , approximately      d.  the amount of time it takes for the amount of money to double in size is    termed the doubling time . And given by           T = ...
The full tutorial is about 439 words long plus attachments.

attachmentlogo

Attachments:
Z.docx (19K) (Preview)