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$5.00 Chemistry worksheet

  • From Chemistry: General-Chemistry
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  • Due on Apr. 11, 2007
  • Asked on Apr. 11, 2007 at 06:53:33AM
Asked by :
JJ38
JJ38
Rating :No Rating
Questions Asked: 5
Tutorials Posted: 0
 
 
Q:
1. Label each of the following as an acid, base or salt, explaining your answer:

a. BaCl2
b. Ca(OH)2
c. HClO4
d. CrI6
e. HC2H3O2

2. Calculate the pH of the following solutions with the given [H+] or [OH-] and indicate whether it is an acid or base:

a. [H+] = 0.0001


b. [OH-] = 0.01


c. [H+] = 0.000001


3. Calculate the molarity of the following solutions

a. 40 grams of Na3PO4 dissolved to make 400 ml of solution

b. 40 grams of C6H12O6 dissolved to make 300 ml of solution


4. Calculate the molarity of the following solutions from this acid-base titration data:

a. If 250 ml of Ba(OH)2 of unknown concentration with a methyl red indicator present is
titrated with [0.325 M] HNO3, the yellow solution turns red after 36.4 ml of the HNO3
is added. What is the molarity of the Ba(OH)2 solution?

b. If 150 ml of HNO3 of unknown concentration with a methyl orange indicator present
is titrated with [0.163 M] KOH, the red solution turns yellow after 28.9 ml of the
KOH is added. What is the molarity of the HNO3 solution?
 

JordanL asked: No problem, I'm at work as well. Glad to help... chemistry can be a pain in the ass sometimes.
To which JJ38 said: Thanks for understanding. I will deposit it in my acct and pay you tonight, I promise. Thank you again.
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  • Posted on Apr 11, 2007 at 3:55:46PM
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JordanL
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A:
Preview: ... base:<br><br>a. [H+] = 0.0001<br>pH = log10[H + ]<br>pH = - log10[0.0001]<br>pH = 4<br><br>b. [OH-] = 0.01<br>pH = - log10[OH-] - 14<br>pH = - log10[0.01] - 14<br>pH = 12<br><br>c. [H+] = 0.000001<br>pH = log10[H + ]<br>pH = - log10[0.000001]<br>pH = 6<br><br><br>3. Calculate the molarity of the following solutions<br><br>a. 40 grams of Na3PO4 dissolved to make 400 ml of solution <br>Na3PO4 = 160 g/mol <br>(160g/mol) / 40g = .25 mol<br><br>0.2 ...

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