Question
$6.50 parallel resonance impedance
- From Engineering: General-Electrical-Engineering , Engineering: General-Engineering
- Closed, but you can still post tutorials
- Due on Jan. 20, 2011
- Asked on Jan 17, 2011 at 8:18:28PM
Q:
You have a parallel resonance circuit. In this circuit you have a coil in series with a resistor which are parallel with a capacitor. The resistor has a value or 250 ohms and the coil has a value of j5000 while the capacitor has a value of -j5000.
What is the impedance of the circuit?
The half-power bandwidth is what percent of the resonance frequency?
What value resistor when placed across the circuits terminals would make the half-power bandwidth 10% of the resonance frequency?
$6.50
Resonance problems Step by Step
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- Posted on Jan 17, 2011 at 10:02:43PM
A:
Preview: ... 240.13 Ohms
The half-power bandwidth is what percent of the resonance frequency?
To solve this part of the problem you have to use the following formula:
BW = fo*100/Q
Where BW is t he half-power bandwidth, fo = resonance frequency and Q = quality factor = xl/r
Then
Q = 5000/250 = 20
BW = ...
The full tutorial is about 229 words long .
$10.00
Entire analysis of parallel resonance circuit
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- Posted on Jan. 19, 2011 at 09:10:50AM
A:
Preview: ... idth.
Let resonant frequency be W
At resonance
admittance should be minimum for parallel resonance
=>capacitive current must be equal to the inductive part of coil current,i:e I l=I c
Let the total potential given be V.
then, I l = V / Z coil
I c = V / Z c
equating this and solving ...
The full tutorial is about 224 words long .
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