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\$6.50parallel resonance impedance

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Q:

You have a parallel resonance circuit. In this circuit you have a coil in series with a resistor which are parallel with a capacitor. The resistor has a value or 250 ohms and the coil has a value of j5000 while the capacitor has a value of -j5000.

What is the impedance of the circuit?

The half-power bandwidth is what percent of the resonance frequency?

What value resistor when placed across the circuits terminals would make the half-power bandwidth 10% of the resonance frequency?

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Resonance problems Step by Step
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Preview: ... 240.13 Ohms The half-power bandwidth is what percent of the resonance frequency? To solve this part of the problem you have to use the following formula: BW = fo*100/Q Where BW is t he half-power bandwidth, fo = resonance frequency and Q = quality factor = xl/r Then Q = 5000/250 = 20 BW = ...

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