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$1.00 A farmer raises chicken and cow. There a

  • From Mathematics: Algebra
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  • Due on Apr. 24, 2009
  • Asked on Apr 21, 2009 at 10:43:19PM
Asked by :
Teairra
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Q:
A farmer raises chicken and cow. There are 34 animals in all. The farmer couts 110 legs on these animals. How many of each animal does the farmer have?
 

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$1.00
how many legs
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  • Posted on Apr 21, 2009 at 10:52:42PM
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Goldentouch4
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A:
Preview: ... equals 13x2 =26 legs so ...
The full tutorial is about 23 words long .
 
$1.00
step by step solution with full explaination
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  • Posted on Apr 21, 2009 at 11:12:24PM
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starboy
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A:
Preview: ... r legs and chicken have two legs<br>so multiply cow by 4 & chicken by 2<br>4*X & 2*Y<br>and to ...
The full tutorial is about 57 words long .
 
$0.25
Here is ur solution neatly showing all steps
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  • Posted on Apr. 22, 2009 at 03:37:39AM
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gkmqc
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A:
Preview: ... 10 legs on these animals. How many of each animal does the farmer have?<br><br>Solution:let there be 'x' number of chickens.<br>So there will b ...
The full tutorial is about 103 words long .
 
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A + solution with detailed explanation
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  • Posted on Apr. 22, 2009 at 03:39:37AM
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niaz_eee
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A:
Preview: ... legs.<br>Similarly , as each cow has 4 legs , '34-x' has total 4*(34-x) legs.<br>According to problem statement,<br>2x+4*(34-x)=110<br>=>2x+1 ...
The full tutorial is about 103 words long .