Question
$5.00 Homework do in a couple of hours need help please! Thank you
- From Mathematics: General-Mathematics
- Closed, but you can still post tutorials
- Due on May. 02, 2009
- Asked on Apr 29, 2009 at 6:10:13PM
Q:
1. Solve for x: x+ sq. root of x-2 and that = 4.
2. Find the nearest tenth, the roots of: 2x/4-x = 3/x-2.
3. Find all real and imaginary solutions to a. w^2=-225, b. 3v^2+4v-1=0, sq. root of 7x + 29 and that equals to x+3.
4. solve using quadriatic formula a. x^2+4x+3, b. -8q^2-2q+1, c. -3x^2-2x-5
5. find b^2-4ac and the number of the real solutions a. 9m^2-24m+16, b. -3x^2+7x=0
6. Find all real solutions x^2+x+sq root of x^2+x then -2=0
7. Find all real and imaginary solutions b^4+13b^2+36=0
2. Find the nearest tenth, the roots of: 2x/4-x = 3/x-2.
3. Find all real and imaginary solutions to a. w^2=-225, b. 3v^2+4v-1=0, sq. root of 7x + 29 and that equals to x+3.
4. solve using quadriatic formula a. x^2+4x+3, b. -8q^2-2q+1, c. -3x^2-2x-5
5. find b^2-4ac and the number of the real solutions a. 9m^2-24m+16, b. -3x^2+7x=0
6. Find all real solutions x^2+x+sq root of x^2+x then -2=0
7. Find all real and imaginary solutions b^4+13b^2+36=0
$5.00
correct solutions
- This tutorial was purchased 1 time and rated A+ by students like you.
- Posted on Apr 29, 2009 at 6:29:52PM
A:
Preview: ... <br>v = -1.54858<br><br>c: sqrt(7x+29) = x+3<br>7x+29 = x^2 + 6x + 9<br>x^2 -x -20 = 0<br>(x-5)(x+4) = 0 but -4 is extraneous<br>x = 5 <br><br><br>4. a:<br>x = -4 +- sqrt(16 - 12) / 2<br>x=-3<br>x=-1<br><br>b:<br>q = 2 +- sqrt(4 + 32 ) / -16 <br>q = 0.25<br>q = -0.5<br><br>c: x = 2 ...
The full tutorial is about 244 words long .